(1/3)(x^-3/4)=(-8/9)(x^-5/3)

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Solution for (1/3)(x^-3/4)=(-8/9)(x^-5/3) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/3)*((x^-3)/4) = (-8/9)*((x^-5)/3) // - (-8/9)*((x^-5)/3)

(1/3)*((x^-3)/4)-((-8/9)*((x^-5)/3)) = 0

(1/3)*((x^-3)/4)+(8/27)*x^-5 = 0

1/12*x^-3+8/27*x^-5 = 0

(1/12*x^2+8/27*x^0)/(x^5) = 0 // * x^10

x^5*(1/12*x^2+8/27*x^0) = 0

x^5

(1/12)*x^2+8/27 = 0

(1/12)*x^2+8/27 = 0

DELTA = 0^2-(4*(1/12)*(8/27))

DELTA = -8/81

DELTA < 0

x in { } 

x belongs to the empty set

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